Doubling Time Practice Problems
Practice problems in rising difficulty plus a boss question. Each has a hint and full working. Exact method and the rule of 70 covered.
Find the exact doubling time at 10% growth per period. Round to 2 decimal places.
A 4-step solving strategy
- 1Step 1 of 4
Read the rate and make it a decimal
Read the rate r in percent from the problem and convert it to a decimal for the exact formula: 7% = 0.07, 3% = 0.03. For the rule of 70 you keep the percent number (7, 3).
- 2Step 2 of 4
Plug into the exact formula
Use t = ln(2) ÷ ln(1 + r). Substitute your decimal, e.g. t = ln(2) ÷ ln(1.03). ln(2) is always a constant ≈ 0.6931.
- 3Step 3 of 4
Evaluate the denominator and divide
Find ln(1 + r) in the denominator and divide: t = 0.6931 ÷ ln(1 + r). Round the result sensibly to two decimal places.
- 4Step 4 of 4
Check with the rule of 70
Estimate 70 ÷ percent rate as a check. For small rates it matches well; if it is far off, the rate is large — then trust the exact value.
Worked practice problems with full working
Common mistakes — and how to avoid them
Rate not converted to a decimal
Mixing up the rule of 70 and the exact formula
Stretching the rule of thumb to large rates
Confusing linear with exponential growth
Confusing ln(2) with log(2)
Practice with a plan — three quick tips
Always compute both ways
Raise the rate systematically
For every wrong answer: why?
Frequently asked questions about practice
Terms in one sentence
- Doubling time
- The time it takes a quantity to double at a constant growth rate: t = ln(2) ÷ ln(1 + r).
- Growth rate
- The percentage increase per period, e.g. 7% per year.
- Rule of 70
- A rule of thumb for estimating: doubling time ≈ 70 ÷ percent rate.
- Rule of 72
- A variant of the rule of thumb using 72 instead of 70 — easier to divide.
- Exponential growth
- Growth at a constant percentage rate; each period multiplies by (1 + r).
- ln (natural logarithm)
- Logarithm to base e; ln(2) ≈ 0.6931.
- Half-life
- The counterpart for decay — the time it takes to halve.