Catenary Calculator
Calculate the catenary curve — the height y = a·cosh(x/a) of a hanging chain at any position x, step by step with the formula, worked examples and FAQ.
Enter values — get full working
Catenary curve — 3 steps
- 1Step 1 of 3
Set the parameter and position
Choose the parameter a (> 0) and the position x where you want the height, e.g. a = 2 and x = 3.
- 2Step 2 of 3
Divide x by a
Form the ratio x/a = 3/2 = 1.5 — the argument of the hyperbolic cosine.
- 3Step 3 of 3
Compute with a·cosh
y = a·cosh(x/a) = 2·cosh(1.5) ≈ 2·2.3524 ≈ 4.70.
Catenary curve — worked examples
The catenary and the hyperbolic cosine
When a flexible chain of uniform weight hangs from just its two ends, it settles under its own weight into the shape of the catenary: y = a·cosh(x/a), where cosh is the hyperbolic cosine, cosh(t) = (eᵗ + e⁻ᵗ)/2. The parameter a controls how flat or steep the curve runs and equals the height of the lowest point above the reference line: at x = 0, cosh(0) = 1, so y = a. As |x| grows, y rises slowly at first, then ever more steeply. The catenary looks similar to a parabola but is not the same curve — it falls away a little more gently. Turned upside down it gives the ideal shape of a self-supporting arch, which is why it appears in architecture (such as the Gateway Arch) and bridge design. Hyperbolic functions like cosh belong to upper-secondary calculus.
Common mistakes
Confusing cosh with cos
Using a = 0 or negative
Forgetting the factor a
Treating it as a parabola
Frequently asked questions
Glossary — key terms explained simply
- Catenary
- Curve of a freely hanging chain, y = a·cosh(x/a).
- Parameter a
- Shape factor and height of the lowest point.
- cosh
- Hyperbolic cosine, (eᵗ + e⁻ᵗ)/2.
- Lowest point
- Position x = 0, where y = a.
- Rise
- Height above the lowest point, y − a.
- Arch
- An inverted catenary as a self-supporting shape.